(u^3-8)/(u-2)

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Solution for (u^3-8)/(u-2) equation: 


D( u )

u-2 = 0

u-2 = 0

u-2 = 0

u-2 = 0 // + 2

u = 2

u in (-oo:2) U (2:+oo)

(u^3-8)/(u-2) = 0

1*u^3 = 8 // : 1

u^3 = 8

u^3 = 8 // ^ 1/3

u = 2

u in { 2} 

u belongs to the empty set

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